m^2+14m=-49

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Solution for m^2+14m=-49 equation: 



m^2+14m=-49

We move all terms to the left:

m^2+14m-(-49)=0

We add all the numbers together, and all the variables

m^2+14m+49=0

a = 1; b = 14; c = +49;
Δ = b2-4ac
Δ = 142-4·1·49
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{-14}{2}=-7$

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